AI-generated practice question — model-generated for extra practice, not a previous-year CBSE board question.
Iron is more reactive than copper, so it displaces copper from copper sulphate solution. The reaction is:
$$\text{Fe}(s) + \text{CuSO}_4(aq) \rightarrow \text{FeSO}_4(aq) + \text{Cu}(s)$$
At the ionic level, iron atoms lose electrons and enter the solution as Fe²⁺ ions, forming iron sulphate (FeSO₄). Simultaneously, Cu²⁺ ions from the solution gain electrons and get deposited as copper metal on the nail. This deposited copper gives the nail a brownish coating. As Cu²⁺ ions are consumed and replaced by Fe²⁺ ions, the concentration of copper sulphate decreases, causing the blue colour to fade.
Source: Chapter 1, Section 1.2.3 — Displacement Reaction
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