AI-generated practice question — model-generated for extra practice, not a previous-year CBSE board question.
The brown fumes are nitrogen dioxide (NO₂). The solid residue formed is lead oxide (PbO).
The reaction is: $2\text{Pb(NO}_3)_2 \xrightarrow{\Delta} 2\text{PbO} + 4\text{NO}_2 + \text{O}_2$. Examiners expect both products named correctly. One mark is typically split: ½ for NO₂, ½ for PbO — so both must be stated.
Source: Chapter 1, Section 1.2.2 (Activity 1.6)