AI-generated practice question — model-generated for extra practice, not a previous-year CBSE board question.
Given: $\tan A = \dfrac{4}{3}$, so the side opposite to A = 4, side adjacent to A = 3.
Finding the hypotenuse using Pythagoras theorem:
$$\text{Hypotenuse}^2 = 4^2 + 3^2 = 16 + 9 = 25$$
$$\text{Hypotenuse} = 5$$
Finding sin A and cos A:
$$\sin A = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{4}{5}$$
$$\cos A = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{3}{5}$$
Source: Chapter 8, Section 8.1 (Trigonometric Ratios)
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