AI-generated practice question — model-generated for extra practice, not a previous-year CBSE board question.
In a right triangle ABC, right-angled at B:
$$\sin A = \frac{\text{side opposite to angle A}}{\text{hypotenuse}} = \frac{BC}{AC}$$
Source: Chapter 8, Section 8.2 Trigonometric Ratios
The examiner expects the definition in words and the fraction with correct sides. BC is opposite to ∠A and AC is the hypotenuse. Do not confuse AB (adjacent side) with BC (opposite side). Writing only the formula without the word definition may lose half the mark.