Using arc length formula: $l = \dfrac{\theta}{360} \times 2\pi r$
$11 = \dfrac{\theta}{360} \times 2 \times \dfrac{22}{7} \times 6.3$
$11 = \dfrac{\theta}{360} \times 39.6$
$\theta = \dfrac{11 \times 360}{39.6} = 100°$
Answer: (D) 100°
The arc length formula from the chapter summary is $l = \dfrac{\theta}{360} \times 2\pi r$. Substitute $l = 11$, $r = 6.3$, $\pi = \frac{22}{7}$, then solve for $\theta$. Note: PQ here refers to the arc length, not the chord. Examiners expect you to state the formula, substitute values, and box the answer clearly.