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Mathematics — Standard (041) — CBSE Class 10 board question

Q1. [1] § 6.4 Criteria for Similarity of Triangles § 6.5 Summary
It is given that $\triangle ABC \sim \triangle EDF$. Which of the following is not true?
  1. A $\dfrac{\text{Perimeter of } \triangle ABC}{\text{Perimeter of } \triangle EDF} = \dfrac{AB}{ED}$
  2. B $\dfrac{AB}{ED} = \dfrac{AC}{EF}$
  3. C $\angle A = \angle D,\ \angle C = \angle F$
  4. D $\dfrac{AB + BC}{DE + DF} = \dfrac{AC}{EF}$
Previously asked in CBSE board exam
2026 30/4/1 Q2
Generated by claude-sonnet-4-6 · 2026-06-15 10:21 · grounding rag
Model Answer

Option C is not true.

Since △ABC ~ △EDF, the correct correspondence is A↔E, B↔D, C↔F. So the correct angle equalities are ∠A = ∠E, ∠B = ∠D, ∠C = ∠F — not ∠A = ∠D.

Answer: C

Explanation

In △ABC ~ △EDF, the order of vertices gives the correspondence: A↔E, B↔D, C↔F. The textbook explicitly states that similarity must be expressed using correct correspondence of vertices (e.g., "we cannot write △ABC ~ △EDF" for a different pairing). Options A, B, and D all hold using the correct ratios (AB/ED, AC/EF, etc.); only C incorrectly states ∠A = ∠D instead of ∠A = ∠E.

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