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Mathematics — Standard (041) — CBSE Class 10 board question

Q1. [1] § 4.4 Nature of Roots § 4.5 Summary
If the quadratic equation $9x^2 + 8kx + 16 = 0$ has real and equal roots, then the value of $k$ is
  1. A $3$
  2. B $-3$
  3. C $-4$
  4. D $\frac{3}{2}$
Previously asked in CBSE board exam
2026 30/4/1 Q1
Generated by claude-sonnet-4-6 · 2026-06-15 10:29 · grounding rag
Model Answer

For equal roots, discriminant = 0: $b^2 - 4ac = 0$.

Here $a = 9$, $b = 8k$, $c = 16$.

$(8k)^2 - 4(9)(16) = 0 \Rightarrow 64k^2 = 576 \Rightarrow k^2 = 9 \Rightarrow k = \pm 3$

Answer: A (3) and B (−3) — both are valid, but the options listed include A: 3 and B: −3.

Source: Chapter 4, Section 4.4

Explanation

For equal roots, use $b^2 - 4ac = 0$. Here $b = 8k$, so $(8k)^2 = 64k^2$. Solving gives $k = ±3$. Both A and B are correct values; if only one option must be chosen, note that the question likely expects both but most MCQs here accept either. Examiners award mark for correct application of discriminant condition.

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Previous-year CBSE Grade 10 board exam questions, organised by subject and chapter, each with a model answer — free to read and print.