📚 CBSE Grade-10 Study Guide
HomeMathematics — Standard (041)

Mathematics — Standard (041) — CBSE Class 10 board question

Q1. [2] § 8.3 Trigonometric Ratios of Some Specific Angles
Evaluate : $2\sqrt{2}\,\cos 45^\circ \sin 30^\circ + 2\sqrt{3}\,\cos 30^\circ$
Previously asked in CBSE board exam
2024 30/1/1 Q23(A)
Generated by claude-sonnet-4-6 · 2026-06-15 10:27 · grounding rag
Model Answer

Substituting standard values: $\cos 45° = \dfrac{1}{\sqrt{2}}$, $\sin 30° = \dfrac{1}{2}$, $\cos 30° = \dfrac{\sqrt{3}}{2}$

$$2\sqrt{2}\cos 45°\sin 30° + 2\sqrt{3}\cos 30°$$

$$= 2\sqrt{2} \times \frac{1}{\sqrt{2}} \times \frac{1}{2} + 2\sqrt{3} \times \frac{\sqrt{3}}{2}$$

$$= 2\sqrt{2} \times \frac{1}{2\sqrt{2}} + 2\sqrt{3} \times \frac{\sqrt{3}}{2}$$

$$= 1 + 3 = \boxed{4}$$

Source: Chapter 8, Section 8.3 (Table 8.1)

---

Explanation
If a question refers to an image, map, graph or diagram that is not shown here, find the actual CBSE question paper on the CBSE website: cbse.gov.in.
Previous-year CBSE Grade 10 board exam questions, organised by subject and chapter, each with a model answer — free to read and print.