📚 CBSE Grade-10 Study Guide
HomeMathematics — Standard (041)

Mathematics — Standard (041) — CBSE Class 10 board question

Q1. [1] § 13.2 Mean of Grouped Data
For some data $x_1, x_2, \ldots\, x_n$ with respective frequencies $f_1, f_2, \ldots\, f_n$, the value of $\sum_{1}^{n} f_i(x_i - \bar{x})$ is equal to :
  1. (a) $n\bar{x}$
  2. (b) 1
  3. (c) $\sum f_i$
  4. (d) 0
Previously asked in CBSE board exam
2024 30/1/1 Q9
Generated by claude-sonnet-4-6 · 2026-06-15 10:36 · grounding rag
Model Answer

(d) 0

Since $\bar{x} = \dfrac{\Sigma f_i x_i}{\Sigma f_i}$, we have $\Sigma f_i x_i = \bar{x} \cdot \Sigma f_i$. Therefore, $\sum f_i(x_i - \bar{x}) = \Sigma f_i x_i - \bar{x}\Sigma f_i = \bar{x}\Sigma f_i - \bar{x}\Sigma f_i = 0$.

Source: Chapter 13, Section 13.2 Mean of Grouped Data

Explanation

This is a standard property of the arithmetic mean: the sum of deviations of observations from their mean is always zero. Expanding $\sum f_i(x_i - \bar{x}) = \sum f_i x_i - \bar{x}\sum f_i$, and substituting the formula for $\bar{x}$, both terms cancel. Examiners expect you to identify option (d) and optionally show the one-step algebraic justification.

If a question refers to an image, map, graph or diagram that is not shown here, find the actual CBSE question paper on the CBSE website: cbse.gov.in.
Previous-year CBSE Grade 10 board exam questions, organised by subject and chapter, each with a model answer — free to read and print.