Q1. [1] § Introduction to Trigonometry (Chapter Header and Quote) § 8.5 Summary
If $\sec\theta - \tan\theta = m$, then the value of $\sec\theta + \tan\theta$ is :
- (a) $1 - \frac{1}{m}$
- (b) $m^2 - 1$
- (c) $\frac{1}{m}$
- (d) $-m$
Previously asked in CBSE board exam
2024 30/1/1 Q7
Generated by claude-sonnet-4-6 · 2026-06-15 10:27 · grounding rag
Model Answer
(c) $\dfrac{1}{m}$
Since $\sec^2\theta - \tan^2\theta = 1$, we have $(\sec\theta - \tan\theta)(\sec\theta + \tan\theta) = 1$, so $\sec\theta + \tan\theta = \dfrac{1}{m}$.
Explanation
Use the identity $\sec^2\theta - \tan^2\theta = 1$, which factors as $(\sec\theta - \tan\theta)(\sec\theta + \tan\theta) = 1$. Since $\sec\theta - \tan\theta = m$, dividing both sides by $m$ gives the answer directly.
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