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Mathematics — Standard (041) — CBSE Class 10 board question

Q1. [1] § 4.4 Nature of Roots
If the roots of equation $ax^2 + bx + c = 0$, $a \neq 0$ are real and equal, then which of the following relation is true ?
  1. (a) $a = \frac{b^2}{c}$
  2. (b) $b^2 = ac$
  3. (c) $ac = \frac{b^2}{4}$
  4. (d) $c = \frac{b^2}{a}$
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Model Answer

(c) $ac = \dfrac{b^2}{4}$

For real and equal roots, the discriminant $b^2 - 4ac = 0$, which gives $b^2 = 4ac$, i.e., $ac = \dfrac{b^2}{4}$.

Source: Chapter 4, Section 4.4 — Nature of Roots

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Explanation

The key condition for equal (coincident) roots is discriminant = 0, i.e., $b^2 - 4ac = 0 \Rightarrow b^2 = 4ac$. Rearranging gives option (c). Options (a), (b), and (d) do not correctly represent this condition — note that (b) $b^2 = ac$ is missing the factor of 4, which is a common trap.

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