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Mathematics — CBSE Class 10 board question

Q1. [2]
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $\frac{3}{5}$, then find the number of yellow balls.
Previously asked in CBSE board exam
2026 30/5/1 Q25
Generated by claude-sonnet-4-6 · 2026-06-15 10:31 · grounding rag
Model Answer

Total number of balls = 25

P(green ball) = 3/5

Number of green balls = (3/5) × 25 = 15

Using complementary events: P(yellow) = 1 − 3/5 = 2/5

Number of yellow balls = (2/5) × 25 = 10

Source: Chapter 14, Section 14.1

Explanation

The examiner expects you to first find the number of green balls (or directly use the complement), then subtract from 25. Both methods are acceptable, but showing the complementary probability step earns full marks. Key formula used: Number of favourable outcomes = P(E) × Total outcomes.

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Previous-year CBSE Grade 10 board exam questions, organised by subject and chapter, each with a model answer — free to read and print.