(A) 11.78 m²
CSA of hemisphere = $2\pi r^2 = 2 \times \dfrac{22}{7} \times 1.4 \times 1.4 = 12.32 \text{ m}^2$
Outer surface area = $12.32 - 0.50 = \mathbf{11.82}$ — wait:
$2 \times \frac{22}{7} \times 1.96 = 12.32\ \text{m}^2$; subtracting door area: $12.32 - 0.50 = 11.82\ \text{m}^2$
(C) 11.82 m²
The tent is hemispherical, so its curved surface area = $2\pi r^2 = 2 \times \frac{22}{7} \times (1.4)^2 = 12.32\ \text{m}^2$. The door opening (0.50 m²) is cut out from this surface, so outer surface area = $12.32 - 0.50 = 11.82\ \text{m}^2$. Key point: subtract only the door area, not the base (hemispherical tent has no floor canvas).