Option D: $a = 0, b = -6$
Sum of zeroes = $2 + (-3) = -1 = -(a+1)$, so $a+1 = 1 \Rightarrow a = 0$.
Product of zeroes = $2 \times (-3) = -6 = b$, so $b = -6$.
Source: Chapter 2, Section 2.3
Use the relations: sum of zeroes $= \frac{-(a+1)}{1}$ and product of zeroes $= \frac{b}{1}$. Plug in zeroes 2 and −3 to get both values directly. Watch out for option C ($a=2, b=-6$) — it has the correct $b$ but wrong $a$, a common trap.