Q1. [1] § Chapter Opening and Epigraph
A bag contains 5 pink, 8 blue and 7 yellow balls. One ball is drawn at random from the bag. What is the probability of getting neither a blue nor a pink ball?
- A $\frac{1}{4}$
- B $\frac{2}{5}$
- C $\frac{7}{20}$
- D $\frac{13}{20}$
Previously asked in CBSE board exam
2023 30/6/1 Q11
Generated by claude-sonnet-4-6 · 2026-06-15 10:31 · grounding rag
Model Answer
Total balls = 5 + 8 + 7 = 20. Neither blue nor pink means only yellow balls are favourable. Number of yellow balls = 7.
$$P(\text{neither blue nor pink}) = \frac{7}{20}$$
Answer: C $\dfrac{7}{20}$
Explanation
"Neither blue nor pink" means the ball must be yellow. Count yellow balls (7) over total balls (20). Eliminate the other two colours — don't add them to the favourable count.
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