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Mathematics — Standard (041) — CBSE Class 10 board question

Q1. [1] § 6.1 Introduction § 6.4 Criteria for Similarity of Triangles
In the given figure, DE||BC. If AD = 3 cm, AB = 7 cm and EC = 3 cm, then the length of AE is
  1. A 2 cm
  2. B 2.25 cm
  3. C 3.5 cm
  4. D 4 cm
Previously asked in CBSE board exam
2023 30/6/1 Q10
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Generated by claude-sonnet-4-6 · 2026-06-15 10:27 · grounding rag
Model Answer

By Basic Proportionality Theorem (DE || BC):

$$\frac{AD}{DB} = \frac{AE}{EC}$$

DB = AB − AD = 7 − 3 = 4 cm

$$\frac{3}{4} = \frac{AE}{3}$$

$$AE = \frac{9}{4} = 2.25 \text{ cm}$$

Answer: (B) 2.25 cm

Source: Chapter 6, Section 6.3 (Theorem 6.1 — Basic Proportionality Theorem)

Explanation

Since DE || BC, Thales' theorem gives AD/DB = AE/EC. Students must first find DB = AB − AD = 4 cm, then substitute EC = 3 cm and solve for AE. The common error is using AB instead of DB in the ratio — always use the two segments on the same side (AD and DB), not the full side.

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