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Mathematics — Standard (041) — CBSE Class 10 board question

Q1. [1] § 4.4 Nature of Roots
If the quadratic equation $ax^2 + bx + c = 0$ has two real and equal roots, then 'c' is equal to
  1. A $\frac{-b}{2a}$
  2. B $\frac{b}{2a}$
  3. C $\frac{-b^2}{4a}$
  4. D $\frac{b^2}{4a}$
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2023 30/6/1 Q9
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Model Answer

Option D: $\dfrac{b^2}{4a}$

For two equal roots, discriminant $= 0$, so $b^2 - 4ac = 0 \Rightarrow c = \dfrac{b^2}{4a}$.

Source: Chapter 4, Section 4.4 Nature of Roots

Explanation

When $b^2 - 4ac = 0$, the equation has two equal real roots. Rearranging gives $c = \dfrac{b^2}{4a}$. Students often confuse this with the root value $\left(\dfrac{-b}{2a}\right)$; remember the question asks for c, not the root.

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