A bag contains 4 red, 3 blue and 2 yellow balls. One ball is drawn at random from the bag. Find the probability that drawn ball is (i) red (ii) yellow.
Generated by claude-sonnet-4-6 · 2026-06-15 10:31 · grounding rag
Model Answer
Total number of balls = 4 + 3 + 2 = 9
(i) P(red ball)
Number of red balls = 4
$$P(\text{red}) = \frac{4}{9}$$
(ii) P(yellow ball)
Number of yellow balls = 2
$$P(\text{yellow}) = \frac{2}{9}$$
Source: Chapter 14, Section 14.1
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Explanation
- Always find the total number of outcomes first (here, 4 + 3 + 2 = 9).
- Apply the formula: P(E) = (Favourable outcomes) ÷ (Total outcomes).
- Each sub-part carries 1 mark; one line with the fraction is sufficient. Simplify if possible (2/9 is already in simplest form).