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Mathematics — Standard (041) — CBSE Class 10 board question

Q1. [1] § 8.3 Trigonometric Ratios of Some Specific Angles
$\left[\dfrac{3}{4}\tan^2 30° - \sec^2 45° + \sin^2 60°\right]$ is equal to
  1. A $-1$
  2. B $\dfrac{5}{6}$
  3. C $\dfrac{-3}{2}$
  4. D $\dfrac{1}{6}$
Previously asked in CBSE board exam
2023 30/1/1 Q9
Generated by claude-sonnet-4-6 · 2026-06-15 10:26 · grounding rag
Model Answer

$$\frac{3}{4}\tan^2 30° - \sec^2 45° + \sin^2 60° = \frac{3}{4}\times\frac{1}{3} - 2 + \frac{3}{4} = \frac{1}{4} - 2 + \frac{3}{4} = 1 - 2 = -1$$

Answer: (A) −1

Explanation

Substitute standard values: $\tan 30° = \frac{1}{\sqrt{3}}$, so $\tan^2 30° = \frac{1}{3}$; $\sec 45° = \sqrt{2}$, so $\sec^2 45° = 2$; $\sin 60° = \frac{\sqrt{3}}{2}$, so $\sin^2 60° = \frac{3}{4}$. Then simplify step by step. Memorise Table 8.1 values — this type of substitution question is very common.

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Previous-year CBSE Grade 10 board exam questions, organised by subject and chapter, each with a model answer — free to read and print.