Option A: 1
For $p(x) = x^2 + x - 1$: $\alpha + \beta = -1$, $\alpha\beta = -1$.
$$\frac{1}{\alpha} + \frac{1}{\beta} = \frac{\alpha + \beta}{\alpha\beta} = \frac{-1}{-1} = 1$$
The key step is rewriting $\frac{1}{\alpha}+\frac{1}{\beta}$ as $\frac{\alpha+\beta}{\alpha\beta}$, then applying Vieta's formulas: sum $= \frac{-b}{a} = -1$ and product $= \frac{c}{a} = -1$. Dividing gives 1. Don't try to find individual zeroes — use the relations directly.