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Mathematics — Standard (041) — CBSE Class 10 board question

Q1. [2] § 7.1 Introduction § 7.2 Distance Formula § 7.3 Section Formula
Find the coordinates of the point C which lies on the line AB produced such that AC = 2BC, where coordinates of points A and B are $(-1, 7)$ and $(4, -3)$ respectively.
Previously asked in CBSE board exam
2025 30/4/1 Q23
Generated by claude-sonnet-4-6 · 2026-06-15 10:31 · grounding rag
Model Answer

Since C lies on line AB produced (beyond B) such that AC = 2BC, point C divides AB externally, with B between A and C.

AC = 2BC ⟹ AC – BC = BC ⟹ AB = BC, so B divides AC in ratio 1 : 1? No —

Since AC = 2BC and C is beyond B: AB + BC = AC = 2BC ⟹ AB = BC.

So B is the midpoint of AC. Let C = (x, y).

Using midpoint formula:
$$4 = \frac{-1 + x}{2} \Rightarrow x = 9$$
$$-3 = \frac{7 + y}{2} \Rightarrow y = -13$$

∴ Coordinates of C = (9, –13)

Source: Chapter 7, Section 7.3 (Section Formula / Midpoint Formula)

Explanation
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