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Science (086) — CBSE Class 10 board question

Q1. [5] § 11.6 RESISTANCE OF A SYSTEM OF RESISTORS § 11.6.1 Resistors in Series
(i) How many bulbs of resistance 8 Ω each should be connected in parallel combination to draw a current of 2 A from a battery of 4 V ? (ii) Name the device used for measuring electric current. How is it connected in a circuit ? (iii) State Joule's law of heating.
Previously asked in CBSE board exam
2026 31/1/1 Q39(b)
Generated by claude-sonnet-4-6 · 2026-06-15 06:41 · grounding rag
Model Answer

(i) Let $n$ bulbs, each of resistance 8 Ω, be connected in parallel.

Equivalent resistance: $R_p = \dfrac{8}{n}$ Ω

Using Ohm's law: $I = \dfrac{V}{R_p}$

$$2 = \frac{4}{8/n} = \frac{4n}{8} = \frac{n}{2}$$

$$n = 4$$

4 bulbs should be connected in parallel.

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(ii) An ammeter is used to measure electric current. It is always connected in series in the circuit, so that the same current flows through it.

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(iii) Joule's Law of Heating: The heat produced in a resistor is

$$H = I^2 R t$$

It states that the heat produced in a conductor is directly proportional to (a) the square of the current ($I^2$), (b) the resistance ($R$) of the conductor, and (c) the time ($t$) for which current flows.

Source: Chapter 11 – Electricity, Sections 11.6.2 and 11.7

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Explanation
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