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Mathematics — CBSE Class 10 board question

Q1. [1]
It is given that $\triangle ABC \sim \triangle QRP$ such that AB = 9 cm, BC = 5 cm and PR = 2 cm. Length of side QR is :
  1. A $0·9$ cm
  2. B $\frac{5}{18}$ cm
  3. C $\frac{10}{9}$ cm
  4. D $3·6$ cm
Previously asked in CBSE board exam
2026 30/3/1 Q13
Generated by claude-sonnet-4-6 · 2026-06-15 10:25 · grounding rag
Model Answer

△ABC ~ △QRP, so the correspondence is: A↔Q, B↔R, C↔P.

Therefore: $\dfrac{AB}{QR} = \dfrac{BC}{RP}$

$\dfrac{9}{QR} = \dfrac{5}{2}$

$QR = \dfrac{9 \times 2}{5} = \dfrac{18}{5} = \mathbf{3.6 \text{ cm}}$

Answer: (D) 3.6 cm

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Explanation

The key is reading the correspondence carefully: △ABC ~ △QRP means A↔Q, B↔R, C↔P. So AB corresponds to QR (not QP). Students often make errors by matching sides without checking the order of vertices. Use $\frac{AB}{QR} = \frac{BC}{RP}$ and substitute known values to get QR.

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Previous-year CBSE Grade 10 board exam questions, organised by subject and chapter, each with a model answer — free to read and print.