Option B: 30°
Let height of tower = h, shadow length = √3h. Then tan θ = h/(√3h) = 1/√3, so θ = 30°.
The altitude of the Sun equals the angle of elevation from the tip of the shadow to the top of the tower. Using tan θ = height/shadow = h/(√3h) = 1/√3 gives θ = 30°. Remember: tan 30° = 1/√3.