Q1. [1] § 9.1 Heights and Distances § 9.2 Summary
If the length of the shadow of a tower is $\sqrt{3}$ times that of its height, then altitude of the Sun is :
- A $45°$
- B $30°$
- C $60°$
- D $15°$
Previously asked in CBSE board exam
2026 30/3/1 Q9
Generated by claude-sonnet-4-6 · 2026-06-15 10:36 · grounding rag
Model Answer
Option B: 30°
Let height of tower = h, shadow length = √3h. Then tan θ = h/(√3h) = 1/√3, so θ = 30°.
Explanation
The altitude of the Sun equals the angle of elevation from the tip of the shadow to the top of the tower. Using tan θ = height/shadow = h/(√3h) = 1/√3 gives θ = 30°. Remember: tan 30° = 1/√3.
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