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Mathematics — Standard (041) — CBSE Class 10 board question

Q1. [1] § 1.2 The Fundamental Theorem of Arithmetic
$(3 \times 11 \times 13 + 3)$ is :
  1. A a prime number
  2. B divisible by 13
  3. C a composite number
  4. D an odd number
Previously asked in CBSE board exam
2026 30/3/1 Q4
Generated by claude-sonnet-4-6 · 2026-06-15 10:30 · grounding rag
Model Answer

Option C: a composite number

$3 \times 11 \times 13 + 3 = 3(11 \times 13 + 1) = 3 \times 144 = 432$, which has factors other than 1 and itself, so it is a composite number.

Explanation

The key is to take 3 common: $3(11 \times 13 + 1) = 3 \times 144$. Since the number has 3 as a factor (and is not 3 itself), it is composite. This directly applies the concept from Exercise 1.1, Q.6 of Chapter 1 — if a number can be expressed as a product of two integers both greater than 1, it is composite. Note: it is even (432), so option D is wrong; and it is divisible by 3, not 13, so B is wrong.

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