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Mathematics — CBSE Class 10 board question

Q1. [5]
Determine graphically, the coordinates of vertices of a triangle whose equations are $2x - 3y + 6 = 0$; $2x + 3y - 18 = 0$ and $x = 0$. Also, find the area of this triangle.
Previously asked in CBSE board exam
2026 30/1/1 Q32
Generated by claude-sonnet-4-6 · 2026-06-15 10:34 · grounding rag
Model Answer

Step 1 – Find points for each line:

Line 1: $2x - 3y + 6 = 0$

| x | 0 | 3 |
|---|---|---|
| y | 2 | 4 |

Line 2: $2x + 3y - 18 = 0$

| x | 0 | 9 |
|---|---|---|
| y | 6 | 0 |

Line 3: $x = 0$ (the y-axis)

Step 2 – Plot and draw all three lines on graph paper.

Step 3 – Read the vertices (intersection points):

Step 4 – Area of triangle:

Base AB lies on y-axis: $AB = 6 - 2 = 4$ units.
Height = perpendicular distance from C(3, 4) to y-axis $= 3$ units.

$$\text{Area} = \frac{1}{2} \times 4 \times 3 = \boxed{6 \text{ sq. units}}$$

Source: Chapter 3, Section 3.2 – Graphical Method of Solution

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Explanation
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