Q1. [1]
The hour hand of a clock is 7 cm long. The angle swept by it between 7:00 a.m. and 8:10 a.m. is :
- (a) $\left(\frac{35}{4}\right)°$
- (b) $\left(\frac{35}{2}\right)°$
- (c) $35°$
- (d) $70°$
Previously asked in CBSE board exam
2026 30/1/1 Q15
Generated by claude-sonnet-4-6 · 2026-06-15 10:37 · grounding rag
Model Answer
The hour hand completes 360° in 12 hours = 0.5° per minute. Time from 7:00 a.m. to 8:10 a.m. = 70 minutes. Angle swept = 70 × 0.5° = 35°.
Answer: (c) 35°
Explanation
- The hour hand takes 12 hours (720 minutes) to complete 360°, so it moves 360/720 = 0.5° per minute.
- The length of the hour hand (7 cm) is irrelevant — the question asks only for the angle, not area or arc length.
- 7:00 a.m. to 8:10 a.m. = 1 hour 10 minutes = 70 minutes.
- Angle = 70 × 0.5° = 35°. Examiners look for this clean calculation; don't confuse with the minute hand's rate (6° per minute).
If a question refers to an image, map, graph or diagram that is not shown here, open the Study Guide single page app, go to
Library and find the actual CBSE question paper. The original papers are also available on the CBSE website:
cbse.gov.in.