Q1. [1] § 11.2 Summary
The hour hand of a clock is 7 cm long. The angle swept by it between 7:00 a.m. and 8:10 a.m. is :
- (a) $\left(\frac{35}{4}\right)°$
- (b) $\left(\frac{35}{2}\right)°$
- (c) $35°$
- (d) $70°$
Previously asked in CBSE board exam
2026 30/1/1 Q15
Generated by claude-sonnet-4-6 · 2026-06-15 10:37 · grounding rag
Model Answer
The hour hand completes 360° in 12 hours = 0.5° per minute. Time from 7:00 a.m. to 8:10 a.m. = 70 minutes. Angle swept = 70 × 0.5° = 35°.
Answer: (c) 35°
Explanation
- The hour hand takes 12 hours (720 minutes) to complete 360°, so it moves 360/720 = 0.5° per minute.
- The length of the hour hand (7 cm) is irrelevant — the question asks only for the angle, not area or arc length.
- 7:00 a.m. to 8:10 a.m. = 1 hour 10 minutes = 70 minutes.
- Angle = 70 × 0.5° = 35°. Examiners look for this clean calculation; don't confuse with the minute hand's rate (6° per minute).
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cbse.gov.in.