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Mathematics — Standard (041) — CBSE Class 10 board question

Q1. [2] § 7.4 Summary
The line segment joining the points $A(4, -5)$ and $B(4, 5)$ is divided by the point $P$ such that $AP : AB = 2 : 5$. Find the coordinates of $P$.
Previously asked in CBSE board exam
2023 30/5/1 Q21 (OR-1)
Generated by claude-sonnet-4-6 · 2026-06-15 10:30 · grounding rag
Model Answer

Given: A(4, −5), B(4, 5), and AP : AB = 2 : 5.

Since AP : AB = 2 : 5, we get AP : PB = 2 : 3.

Using the section formula with $m_1 : m_2 = 2 : 3$:

$$x = \frac{2(4) + 3(4)}{2+3} = \frac{8+12}{5} = 4$$

$$y = \frac{2(5) + 3(-5)}{2+3} = \frac{10-15}{5} = -1$$

∴ Coordinates of P are (4, −1).

Source: Chapter 7, Section 7.3 — Section Formula

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Explanation
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