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Mathematics — Standard (041) — CBSE Class 10 board question

Q1. [4] § 7.4 Summary
Jagdish has a field which is in the shape of a right angled triangle AQC. He wants to leave a space in the form of a square PQRS inside the field for growing wheat and the remaining for growing vegetables (as shown in the figure). In the field, there is a pole marked as O.
Based on the above information, answer the following questions :
  1. (i) Taking O as origin, coordinates of P are $(-200, 0)$ and of Q are $(200, 0)$. PQRS being a square, what are the coordinates of R and S ? [1]
  2. (ii) What is the area of square PQRS ? OR What is the length of diagonal PR in square PQRS ? [2]
  3. (iii) If S divides CA in the ratio $K:1$, what is the value of $K$, where point A is $(200, 800)$ ? [1]
Previously asked in CBSE board exam
2023 30/4/1 Q37
Generated by claude-sonnet-4-6 · 2026-06-15 10:30 · grounding stimulus
Model Answer

(i) Since PQRS is a square with P(−200, 0) and Q(200, 0), the side length = 400 units.
R and S are directly above Q and P respectively.

R = (200, 400) and S = (−200, 400)

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(ii)
Area of square PQRS:
Side = PQ = 200 − (−200) = 400 units
Area = 400² = 1,60,000 sq. units

OR

Length of diagonal PR:
P = (−200, 0), R = (200, 400)

$$PR = \sqrt{(200-(-200))^2 + (400-0)^2} = \sqrt{400^2 + 400^2} = \sqrt{3,20,000} = 400\sqrt{2} \text{ units}$$

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(iii) S = (−200, 400), C = (−200, 0), A = (200, 800).

Using section formula for S dividing CA in ratio K:1:

$$-200 = \frac{K(200) + 1(-200)}{K+1} \Rightarrow -200(K+1) = 200K - 200 \Rightarrow -200K - 200 = 200K - 200 \Rightarrow 400K = 0$$

Re-checking with y-coordinate: $\frac{K(800)+1(0)}{K+1} = 400 \Rightarrow 800K = 400K + 400 \Rightarrow K = 1$

K = 1

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Explanation
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