(d) $\dfrac{12}{13}$
Total cards = 52; number of aces = 4; cards that are not aces = 48.
$$P(\text{not an ace}) = \frac{48}{52} = \frac{12}{13}$$
Source: Chapter 14, Example 4(ii)
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The examiner expects you to recall that a deck has 4 aces, leaving 48 non-ace cards. Dividing 48 by 52 and simplifying gives $\frac{12}{13}$. You can also use the complement: $1 - \frac{1}{13} = \frac{12}{13}$. Either method is acceptable; just show the key step.