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Mathematics — Standard (041) — CBSE Class 10 board question

Q1. [1] § 6.1 Introduction § 6.3 Similarity of Triangles
In $\triangle ABC$, $PQ \parallel BC$. If $PB = 6$ cm, $AP = 4$ cm, $AQ = 8$ cm, find the length of $AC$.
  1. (a) $12$ cm
  2. (b) $20$ cm
  3. (c) $6$ cm
  4. (d) $14$ cm
Previously asked in CBSE board exam
2023 30/4/1 Q16
Generated by claude-sonnet-4-6 · 2026-06-15 10:24 · grounding rag
Model Answer

(b) 20 cm

By Basic Proportionality Theorem, since PQ ∥ BC:
$$\frac{AP}{PB} = \frac{AQ}{QC} \Rightarrow \frac{4}{6} = \frac{8}{QC} \Rightarrow QC = 12 \text{ cm}$$
$$AC = AQ + QC = 8 + 12 = \mathbf{20 \text{ cm}}$$

Source: Chapter 6, Theorem 6.1 (Basic Proportionality Theorem)

Explanation

Apply BPT: since PQ ∥ BC, the line divides AB and AC in the same ratio → AP/PB = AQ/QC. Solve for QC, then add AQ + QC to get AC. A common mistake is giving QC (12 cm) as the answer instead of the full length AC (20 cm).

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