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Mathematics — CBSE Class 10 board question

Q1. [4]
Computer-based learning (CBL) refers to any teaching methodology that makes use of computers for information transmission. At an elementary school level, computer applications can be used to display multimedia lesson plans. A survey was done on 1000 elementary and secondary schools of Assam and they were classified by the number of computers they had.
One school is chosen at random. Then:
  1. (i) Find the probability that the school chosen at random has more than 100 computers. [1]
  2. (ii) Find the probability that the school chosen at random has 50 or fewer computers. [2]
  3. (iii) Find the probability that the school chosen at random has 10 or less than 10 computers. [1]
Previously asked in CBSE board exam
2023 30/2/1 Q38
Generated by claude-sonnet-4-6 · 2026-06-15 10:30 · grounding stimulus
Model Answer

Total number of schools = 1000

(i) Schools with more than 100 computers = 80

$$P(\text{more than 100 computers}) = \frac{80}{1000} = \frac{2}{25}$$

(ii) Schools with 50 or fewer computers = schools in (1–10) + (11–20) + (21–50)
= 250 + 200 + 290 = 740

$$P(\text{50 or fewer computers}) = \frac{740}{1000} = \frac{37}{50}$$

(iii) Schools with 10 or fewer computers = 250

$$P(\text{10 or fewer computers}) = \frac{250}{1000} = \frac{1}{4}$$

Source: Statistics, Probability (Empirical/Experimental Probability)

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Explanation
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