(b) $\dfrac{3}{50}$
Perfect cubes from 1 to 100: 1³=1, 2³=8, 3³=27, 4³=64, 5³=125 (>100). So favourable outcomes = 4.
$$P = \frac{4}{100} = \frac{1}{25}$$
(c) $\dfrac{1}{25}$ is the correct answer.
The perfect cubes between 1 and 100 are 1, 8, 27, and 64 — that is 4 numbers. Using the formula P(E) = favourable outcomes / total outcomes = 4/100 = 1/25. Option (b) 3/50 = 6/100, which would need 6 perfect cubes — incorrect. Watch out: 5³ = 125 > 100, so it is excluded. The correct option is (c).