Q1. [2]
A carton consists of 60 shirts of which 48 are good, 8 have major defects and 4 have minor defects. Nigam, a trader, will accept the shirts which are good but Anmol, another trader, will only reject the shirts which have major defects. One shirt is drawn at random from the carton. Find the probability that it is acceptable to Anmol.
Previously asked in CBSE board exam
2024 30/5/1 Q25
Generated by claude-sonnet-4-6 · 2026-06-15 10:29 · grounding rag
Model Answer
Total number of shirts = 60
Anmol rejects only shirts with major defects (8 shirts). So, shirts acceptable to Anmol = 60 − 8 = 52 (good + minor defect shirts).
$$P(\text{acceptable to Anmol}) = \frac{52}{60} = \frac{13}{15}$$
Source: Chapter 14, Example 12
Explanation
This is modelled on Example 12 from the textbook. The key point is reading the condition carefully: Anmol only rejects major defect shirts, so both good shirts (48) and minor defect shirts (4) are acceptable to him — giving 52 favourable outcomes out of 60. Simplify the fraction to lowest terms for full marks.
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