Q1. [1]
At some time of the day, the length of the shadow of a tower is equal to its height. Then, the Sun's altitude at that time is :
- A 30°
- B 45°
- C 60°
- D 90°
Previously asked in CBSE board exam
2024 30/4/1 Q14
Generated by claude-sonnet-4-6 · 2026-06-15 10:35 · grounding rag
Model Answer
Option B: 45°
When shadow length = height of tower, tan θ = height/shadow = 1, so θ = 45°.
Explanation
Let tower height = h; shadow length = h. Sun's altitude = angle of elevation θ, so tan θ = h/h = 1 ⟹ θ = 45°. Remember: tan 45° = 1 is a standard trigonometric value.
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