Q1. [1] § 9.1 Heights and Distances § 9.2 Summary
At some time of the day, the length of the shadow of a tower is equal to its height. Then, the Sun's altitude at that time is :
- A 30°
- B 45°
- C 60°
- D 90°
Previously asked in CBSE board exam
2024 30/4/1 Q14
Generated by claude-sonnet-4-6 · 2026-06-15 10:35 · grounding rag
Model Answer
Option B: 45°
When shadow length = height of tower, tan θ = height/shadow = 1, so θ = 45°.
Explanation
Let tower height = h; shadow length = h. Sun's altitude = angle of elevation θ, so tan θ = h/h = 1 ⟹ θ = 45°. Remember: tan 45° = 1 is a standard trigonometric value.
If a question refers to an image, map, graph or diagram that is not shown here, find the actual CBSE question paper on the CBSE website:
cbse.gov.in.