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Mathematics — Standard (041) — CBSE Class 10 board question

Q1. [1] § 14.1 Probability — A Theoretical Approach
Two dice are tossed simultaneously. The probability of getting odd numbers on both the dice is :
  1. A $\dfrac{6}{36}$
  2. B $\dfrac{3}{36}$
  3. C $\dfrac{12}{36}$
  4. D $\dfrac{9}{36}$
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2024 30/4/1 Q8
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Model Answer

Answer: D $\dfrac{9}{36}$

Total outcomes = 36. Odd numbers on a die: 1, 3, 5 (3 outcomes). Favourable outcomes (odd, odd) = 3 × 3 = 9. So P = $\dfrac{9}{36}$.

Source: Chapter 14, Section 14.1

Explanation

When two dice are thrown, total outcomes = 6 × 6 = 36. Each die has 3 odd numbers (1, 3, 5), so favourable outcomes = 3 × 3 = 9. Remember to list sample space systematically as shown in Example 13.

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