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Mathematics — Standard (041) — CBSE Class 10 board question

Q1. [2] § 7.2 Distance Formula § 7.3 Section Formula § 7.4 Summary
Points $A(-1, y)$ and $B(5, 7)$ lie on a circle with centre $O(2, -3y)$ such that $AB$ is a diameter of the circle. Find the value of $y$. Also, find the radius of the circle.
Previously asked in CBSE board exam
2024 30/3/1 Q23(b) (OR-2)
Generated by claude-sonnet-4-6 · 2026-06-15 10:29 · grounding rag
Model Answer

Since AB is a diameter and O is the centre, O is the midpoint of AB.

Using the midpoint formula:

$$\frac{-1+5}{2} = 2 \quad \checkmark$$

$$\frac{y+7}{2} = -3y$$

$$y + 7 = -6y$$

$$7y = -7 \implies y = -1$$

So A = (−1, −1) and B = (5, 7).

Radius = $\frac{1}{2}AB = \frac{1}{2}\sqrt{(5-(-1))^2+(7-(-1))^2} = \frac{1}{2}\sqrt{36+64} = \frac{1}{2}\times 10 = 5$ units.

y = −1; Radius = 5 units.

Source: Chapter 7, Section 7.3 (Midpoint Formula) and Section 7.2 (Distance Formula)

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Explanation
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