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Mathematics — Standard (041) — CBSE Class 10 board question

Q1. [1] § 6.1 Introduction § 6.3 Similarity of Triangles § 6.4 Criteria for Similarity of Triangles
In $\triangle ABC$, $DE \parallel BC$ (as shown in the figure). If $AD = 2$ cm, $BD = 3$ cm, $BC = 7.5$ cm, then the length of $DE$ (in cm) is :
  1. A $2.5$
  2. B $3$
  3. C $5$
  4. D $6$
Previously asked in CBSE board exam
2024 30/3/1 Q12
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Generated by claude-sonnet-4-6 · 2026-06-15 10:23 · grounding rag
Model Answer

Since DE ∥ BC, △ADE ~ △ABC (AA similarity).

$$\frac{AD}{AB} = \frac{DE}{BC}$$

AB = AD + DB = 2 + 3 = 5 cm

$$\frac{DE}{7.5} = \frac{2}{5} \implies DE = \frac{2 \times 7.5}{5} = \mathbf{3 \text{ cm}}$$

Answer: (B) 3

Source: Chapter 6, Section 6.3 (Basic Proportionality Theorem / AA Similarity)

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Explanation

Since DE ∥ BC, by AA similarity criterion △ADE ~ △ABC. The key ratio is AD/AB (not AD/BD). Students often mistakenly use AD/BD = 2/3 directly — that gives the wrong answer. Always find the full side AB = AD + DB = 5 cm first, then apply the ratio AD/AB = 2/5 to find DE.

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