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Mathematics — CBSE Class 10 board question

Q1. [4]
The word 'circus' has the same root as 'circle'. In a closed circular area, various entertainment acts including human skill and animal training are presented before the crowd. A circus tent is cylindrical upto a height of 8 m and conical above it. The diameter of the base is 28 m and total height of tent is 18.5 m.
The word 'circus' has the same root as 'circle'. In a closed circular area, various entertainment acts including human skill and animal training are presented before the crowd. A circus tent is cylindrical upto a height of 8 m and conical above it. The diameter of the base is 28 m and total height of tent is 18.5 m. Based on the above, answer the following questions:
  1. (i) Find slant height of the conical part. [1]
  2. (ii) Determine the floor area of the tent. [1]
  3. (iii) Find area of the cloth used for making tent. OR Find total volume of air inside an empty tent. [2]
Previously asked in CBSE board exam
2024 30/2/1 Q37
Generated by claude-sonnet-4-6 · 2026-06-15 10:33 · grounding stimulus
Model Answer

Given: Diameter = 28 m → Radius (r) = 14 m, Height of cylinder (h₁) = 8 m, Total height = 18.5 m → Height of cone (h₂) = 18.5 − 8 = 10.5 m

(i) Slant height of conical part:

$$l = \sqrt{r^2 + h_2^2} = \sqrt{14^2 + 10.5^2} = \sqrt{196 + 110.25} = \sqrt{306.25} = 17.5 \text{ m}$$

(ii) Floor area of tent:

$$= \pi r^2 = \frac{22}{7} \times 14 \times 14 = 616 \text{ m}^2$$

(iii) Area of cloth used (CSA of cylinder + CSA of cone):

$$= 2\pi r h_1 + \pi r l = \pi r(2h_1 + l) = \frac{22}{7} \times 14 \times (16 + 17.5) = 44 \times 33.5 = \mathbf{1474 \text{ m}^2}$$

OR Total volume of air:

$$= \pi r^2 h_1 + \frac{1}{3}\pi r^2 h_2 = \pi r^2\!\left(h_1 + \frac{h_2}{3}\right) = \frac{22}{7} \times 196 \times \left(8 + 3.5\right) = 616 \times 11.5 = \mathbf{7084 \text{ m}^3}$$

Source: Mensuration (Cylinders and Cones), Class 10 Mathematics

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Explanation
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