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Mathematics — Standard (041) — CBSE Class 10 board question

Q1. [1] § 5.5 Summary
The common difference of an A.P. in which $a_{15} - a_{11} = 48$, is
  1. (A) $12$
  2. (B) $16$
  3. (C) $-12$
  4. (D) $-16$
Previously asked in CBSE board exam
2024 30/2/1 Q3
Generated by claude-sonnet-4-6 · 2026-06-15 10:31 · grounding rag
Model Answer

(A) 12

$a_{15} - a_{11} = [a+14d] - [a+10d] = 4d = 48 \Rightarrow d = 12$

Explanation

Use $a_n = a+(n-1)d$. Subtracting the two terms eliminates $a$, leaving $4d = 48$, so $d = 12$. Only option (A) matches.

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