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Mathematics — Standard (041) — CBSE Class 10 board question

Q1. [2] § 8.3 Trigonometric Ratios of Some Specific Angles § 8.5 Summary
If $4k = \tan^2 60^\circ - 2\cosec^2 30^\circ - 2\tan^2 30^\circ$, then find the value of $k$.
Previously asked in CBSE board exam
2025 30/3/1 Q21
Generated by claude-sonnet-4-6 · 2026-06-15 10:22 · grounding rag
Model Answer

Given: $4k = \tan^2 60° - 2\cosec^2 30° - 2\tan^2 30°$

Substituting values: $\tan 60° = \sqrt{3}$, $\cosec 30° = 2$, $\tan 30° = \dfrac{1}{\sqrt{3}}$

$$4k = (\sqrt{3})^2 - 2(2)^2 - 2\left(\frac{1}{\sqrt{3}}\right)^2$$

$$4k = 3 - 2(4) - 2\left(\frac{1}{3}\right)$$

$$4k = 3 - 8 - \frac{2}{3} = -5 - \frac{2}{3} = \frac{-17}{3}$$

$$k = \frac{-17}{12}$$

Source: Chapter 8, Section 8.3 (Table 8.1)

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Explanation
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