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Mathematics — Standard (041) — CBSE Class 10 board question

Q1. [1] § 7.4 Summary
Two of the vertices of $\triangle PQR$ are $P(-1, 5)$ and $Q(5, 2)$. The coordinates of a point which divides PQ in the ratio $2:1$ are:
  1. A $(3, -3)$
  2. B $(5, 5)$
  3. C $(3, 3)$
  4. D $(5, 1)$
Previously asked in CBSE board exam
2025 30/3/1 Q7
Generated by claude-sonnet-4-6 · 2026-06-15 10:28 · grounding rag
Model Answer

(C) (3, 3)

Using the section formula with P(−1, 5), Q(5, 2), ratio 2:1:
$x = \frac{2(5)+1(-1)}{3} = 3$, $y = \frac{2(2)+1(5)}{3} = 3$.

Source: Chapter 7, Section 7.3 (Section Formula)

Explanation

Apply the section formula directly: $\left(\frac{m_1x_2+m_2x_1}{m_1+m_2},\ \frac{m_1y_2+m_2y_1}{m_1+m_2}\right)$ with $m_1=2,\ m_2=1$. A common mistake is swapping the ratio or the points — always assign $m_1$ to the part nearer to the first point listed.

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