Q1. [1] § 2.2 Geometrical Meaning of the Zeroes of a Polynomial § 2.3 Relationship between Zeroes and Coefficients of a Polynomial
If $4$ is a zero of the polynomial $p(x) = x^2 - x - (2 + 2k)$, then the value of $k$ is :
- A $3$
- B $-9$
- C $6$
- D $-3$
Previously asked in CBSE board exam
2025 30/2/1 Q16
Generated by claude-sonnet-4-6 · 2026-06-15 10:34 · grounding rag
Model Answer
(A) 3
Since 4 is a zero, $p(4) = 0$: $4^2 - 4 - (2 + 2k) = 0 \Rightarrow 16 - 4 - 2 - 2k = 0 \Rightarrow 10 = 2k \Rightarrow k = 3$.
Explanation
Substitute x = 4 into p(x) and set it equal to zero (definition of a zero). Solve the resulting linear equation for k. The key concept is: k is a zero of p(x) if p(k) = 0 (Chapter 2, Section 2.1).
If a question refers to an image, map, graph or diagram that is not shown here, find the actual CBSE question paper on the CBSE website:
cbse.gov.in.