📚 CBSE Grade-10 Study Guide
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Mathematics — Standard (041) — CBSE Class 10 board question

Q1. [2] § 8.3 Trigonometric Ratios of Some Specific Angles
Evaluate: $\dfrac{\sin^2 30° + \cos^2 60°}{1 + \tan^2 45°}$
Previously asked in CBSE board exam
2025 30/1/1 Q21 (OR-2)
Generated by claude-sonnet-4-6 · 2026-06-15 10:22 · grounding rag
Model Answer

Using standard values: $\sin 30° = \dfrac{1}{2}$, $\cos 60° = \dfrac{1}{2}$, $\tan 45° = 1$

$$\frac{\sin^2 30° + \cos^2 60°}{1 + \tan^2 45°} = \frac{\left(\dfrac{1}{2}\right)^2 + \left(\dfrac{1}{2}\right)^2}{1 + (1)^2}$$

$$= \frac{\dfrac{1}{4} + \dfrac{1}{4}}{1 + 1} = \frac{\dfrac{1}{2}}{2} = \boxed{\dfrac{1}{4}}$$

Source: Chapter 8, Section 8.3 (Table 8.1)

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Explanation
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