Q1. [1] § 9.1 Heights and Distances § 9.2 Summary
A kite is flying at a height of 150 m from the ground. It is attached to a string inclined at an angle of $30°$ to the horizontal. The length of the string is:
- A $100\sqrt{3}$ m
- B $300$ m
- C $150\sqrt{3}$ m
- D $150\sqrt{2}$ m
Previously asked in CBSE board exam
2025 30/1/1 Q17
Generated by claude-sonnet-4-6 · 2026-06-15 10:34 · grounding rag
Model Answer
Option B: 300 m
Using $\sin 30° = \dfrac{\text{height}}{\text{string length}}$, we get $\dfrac{1}{2} = \dfrac{150}{L}$, so $L = 300$ m.
Explanation
The height (150 m) is the side opposite the 30° angle, and the string is the hypotenuse. Use $\sin\theta = \text{opposite}/\text{hypotenuse}$. $\sin 30° = \frac{1}{2}$, giving $L = 150 \times 2 = 300$ m. Don't confuse with $\tan$ or $\cos$ here.
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