Dry HCl gas does not change the colour of dry blue litmus paper, but HCl dissolved in water (hydrochloric acid) does. Explain this observation at the ionic level. How does this support the statement that 'acids produce H⁺ ions only in the presence of water'? Also write the equation showing how H⁺ ions actually exist in aqueous solution.
Generated by claude-sonnet-4-6 · 2026-06-15 06:42 · grounding rag
Model Answer
Observation: Dry HCl gas does not change the colour of dry blue litmus paper, but HCl dissolved in water (hydrochloric acid) turns blue litmus red.
Ionic-level explanation:
- Litmus (an acid-base indicator) changes colour only in the presence of H⁺ (aq) ions.
- In dry HCl gas, there is no water. HCl molecules remain as molecules and do not ionise — no H⁺ ions are produced. Hence, no colour change occurs.
- When HCl dissolves in water, water molecules cause the separation of H⁺ ions from HCl:
$$\text{HCl} + \text{H}_2\text{O} \rightarrow \text{H}_3\text{O}^+ + \text{Cl}^-$$
- These H⁺ (aq) ions are responsible for the acidic properties, so blue litmus turns red.
Support for the statement: Since HCl shows acidic behaviour only when dissolved in water (i.e., only when H⁺ ions are produced), this proves that acids produce H⁺ ions only in the presence of water.
How H⁺ ions actually exist in aqueous solution:
H⁺ ions cannot exist alone; they combine with water to form the hydronium ion:
$$\text{H}^+ + \text{H}_2\text{O} \rightarrow \text{H}_3\text{O}^+$$
Thus, H⁺ ions always exist as H⁺(aq) or H₃O⁺ in aqueous solution.
Source: Chapter 2, Section 2.2.1
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Explanation
- Key examiner expectation: Students must clearly distinguish dry HCl (no ionisation, no H⁺) from aqueous HCl (ionises to give H⁺), and link this to why the litmus test fails for dry gas.
- Both equations — HCl + H₂O → H₃O⁺ + Cl⁻, and H⁺ + H₂O → H₃O⁺ — are likely to fetch dedicated marks; write both.
- Use the term hydronium ion (H₃O⁺) — examiners look for it.
- The statement "acids produce H⁺ ions only in the presence of water" is directly from the textbook conclusion of Activity 2.9; connect your explanation explicitly to it.