📚 CBSE Grade-10 Study Guide
HomeScience (086)

Science (086) — CBSE Class 10 board question

Q1. [1] § 13.1.1 Food Chains and Webs
Consider the following food chain : Grass → Grasshopper → Frog → Snake → Eagle If the amount of energy available at third trophic level is 50 kJ, the available energy at the producer level was :
  1. (A) 0.5 kJ
  2. (B) 5 kJ
  3. (C) 500 kJ
  4. (D) 5000 kJ
Previously asked in CBSE board exam
2025 31/6/1 Q15
Generated by claude-sonnet-4-6 · 2026-06-15 06:44 · grounding rag
Model Answer

(D) 5000 kJ

Using the 10% law: Third trophic level (Frog) = 50 kJ → Second trophic level = 500 kJ → First trophic level (Grass/Producer) = 5000 kJ.

Explanation

At each trophic level, only 10% of energy passes to the next level. So to find the energy at a lower level, multiply by 10. Third trophic level = 50 kJ, so second = 50 × 10 = 500 kJ, and producer level = 500 × 10 = 5000 kJ. Remember: Frog is at the third trophic level (Grass→1st, Grasshopper→2nd, Frog→3rd).

If a question refers to an image, map, graph or diagram that is not shown here, find the actual CBSE question paper on the CBSE website: cbse.gov.in.
Previous-year CBSE Grade 10 board exam questions, organised by subject and chapter, each with a model answer — free to read and print.