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Science — CBSE Class 10 board question

Q1. [5]
(A) (i) Draw the structure of the following compounds : (a) Butanoic acid (b) Chloropentane (ii) How are structure (i) and structure (ii) given below related to one another ? Give reason to justify your answer. Draw one more possible structure for above case. (iii) Differentiate between saturated and unsaturated carbon compounds on the basis of their general formula.
Previously asked in CBSE board exam
2023 31/4/1 Q34 (A)
Generated by claude-sonnet-4-6 · 2026-06-15 06:48 · grounding rag
Model Answer

(i) Structures:

(a) Butanoic acid (C₃H₇COOH):

$$\text{CH}_3 - \text{CH}_2 - \text{CH}_2 - \text{COOH}$$

(b) Chloropentane (C₅H₁₁Cl):

$$\text{CH}_3 - \text{CH}_2 - \text{CH}_2 - \text{CH}_2 - \text{CH}_2 - \text{Cl}$$

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(ii) Structures (i) and (ii) are related as structural isomers.

Reason: Both have the same molecular formula but different structural arrangements. Such compounds with identical molecular formula but different structures are called structural isomers.

One more possible structure (e.g., for C₄H₁₀):

$$\text{CH}_3 - \underset{|}{\overset{|}{\text{CH}}} (\text{CH}_3) - \text{CH}_3 \quad \text{(2-methylpropane)}$$

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(iii) Difference based on general formula:

| | Saturated | Unsaturated |
|---|---|---|
| General formula | CₙH₂ₙ₊₂ (alkanes) | CₙH₂ₙ (alkenes) / CₙH₂ₙ₋₂ (alkynes) |
| Bonds | Only single bonds | Double or triple bonds between C atoms |

Source: Chapter 4 — Carbon and its Compounds, Sections 4.2.1 and 4.2.2

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Explanation
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