I notice the actual circuit diagram values between points A and B are not fully specified in the passage provided. I'll answer based on the most common version of this CBSE circuit question, where between A and B there are two 8 Ω resistors in series, and between B and C there is a 16 Ω resistor in parallel with two 8 Ω resistors in series.
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(a) Resistance between A and B:
The two 8 Ω resistors between A and B are connected in series.
$$R_{AB} = 8 + 8 = \textbf{16 Ω}$$
(b) Resistance between B and C:
The two 8 Ω resistors are in series → 8 + 8 = 16 Ω. This combination is in parallel with the 16 Ω resistor.
$$R_{BC} = \frac{16 \times 16}{16 + 16} = \frac{256}{32} = \textbf{8 Ω}$$
(c)(i) Total resistance of the circuit:
$$R_{total} = R_{AB} + R_{BC} = 16 + 8 = \textbf{24 Ω}$$
(c)(ii) If battery EMF = 6 V (assumed), current in circuit:
$$I = \frac{V}{R} = \frac{6}{24} = \textbf{0.25 A}$$
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