Q1. [1]
A rectangular loop ABCD carrying a current I is situated near a straight conductor XY, such that the conductor is parallel to the side AB of the loop and is in the plane of the loop. If a steady current I is established in the conductor as shown, the conductor XY will :
- A remain stationary.
- B move towards the side AB of the loop.
- C move away from the side AB of the loop.
- D rotate about its axis.
Previously asked in CBSE board exam
2024 31/4/1 Q15
Generated by claude-sonnet-4-6 · 2026-06-15 06:48 · grounding rag
Model Answer
Answer: (B) move towards the side AB of the loop.
The current in XY and side AB flow in the same direction, so they attract each other (parallel currents attract). Hence, XY moves towards AB.
Explanation
- Two parallel conductors carrying currents in the same direction attract each other; in opposite directions, they repel.
- From the figure, the current in XY is parallel and in the same direction as in side AB, so the force is attractive — XY moves towards AB.
- This is based on the principle from Section 12.3: a current-carrying conductor in a magnetic field experiences a force, and the magnetic field of the loop exerts a force on XY.
- Source: Chapter 12, Section 12.3.
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